0=-0.01x^2+0.3x+2

Solution for 0=-0.01x^2+0.3x+2 equation:

0=-0.01x^2+0.3x+2

We move all terms to the left:

0-(-0.01x^2+0.3x+2)=0

We add all the numbers together, and all the variables

-(-0.01x^2+0.3x+2)=0

We get rid of parentheses

0.01x^2-0.3x-2=0

a = 0.01; b = -0.3; c = -2;
Δ = b2-4ac
Δ = -0.32-4·0.01·(-2)
Δ = 0.17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{0.17}}{2*0.01}=\frac{0.3-\sqrt{0.17}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{0.17}}{2*0.01}=\frac{0.3+\sqrt{0.17}}{0.02}
$